Initial Calculations
Degree of freedom = n-1
= 2-1 = 1 Critical Value: 3.84146 |
Expected Values:
It is expected that to accept the null hypothesis, there is no difference in distribution of the species between acidic and alkaline conditions. |
Species
Table A
|
Acidic |
Alkaline |
Total |
||||
O |
E |
X2 |
O |
E |
X2 |
||
Absent |
2 |
3 |
0.33 |
3 |
2 |
0.5 |
5 |
Present |
4 |
3 |
0.33 |
1 |
2 |
0.5 |
5 |
Total |
6 |
|
|
4 |
|
|
10 |
Table B
|
Acidic |
Alkaline |
Total |
||||
O |
E |
X2 |
O |
E |
X2 |
||
Absent |
3 |
1.8 |
0.8 |
0 |
1.2 |
1.2 |
3 |
Present |
3 |
4.2 |
0.34 |
4 |
2.8 |
0.51 |
7 |
Total |
6 |
|
|
4 |
|
|
10 |
Table C
|
Acidic |
Alkaline |
Total |
||||
O |
E |
X2 |
O |
E |
X2 |
||
Absent |
2 |
2.4 |
0.07 |
2 |
1.6 |
0.1 |
4 |
Present |
4 |
3.6 |
0.04 |
2 |
2.4 |
0.07 |
6 |
Total |
6 |
|
|
4 |
|
|
10 |